Given an array of integers, find if the array contains any duplicates. Your function should return true if any value appears at least twice in the array, and it should return false if every element is distinct.

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代码：

方法一：

1 public class Solution { 2     public boolean containsDuplicate(int[] nums) { 3         Set
     
       hs = new HashSet
      
       (); 4         for (int i = 0; i < nums.length; ++i) { 5             if (hs.contains(nums[i])) { 6                 return true; 7             } 8             hs.add(nums[i]); 9         }10         return false;11     }12 }
      
     

 

方法二：

1 public class Solution { 2     public boolean containsDuplicate(int[] nums) { 3         Arrays.sort(nums); 4         for (int i = 1; i < nums.length; ++i) { 5             if (nums[i] == nums[i - 1]) { 6                 return true; 7             } 8         } 9         return false;10     }11 }